Posted by suraj suwal on Wednesday, September 14, 2011 at 12:38am.
A tennis ball with a speed of 25.9 m/s is
moving perpendicular to a wall. After striking
the wall, the ball rebounds in the opposite
direction with a speed of 21.3157 m/s.
If the ball is in contact with the wall for
0.0133 s, what is the average acceleration of
the ball while it is in contact with the wall?

uta  SraJMcGin, Wednesday, September 14, 2011 at 1:33am
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Sra

physics  drwls, Wednesday, September 14, 2011 at 5:10am
Divide the velocity change by the time interval. Note that the bounceback velocity is negative.
Acceleration = [25.9 (21.3157)]/0.0133
= 3550 m/s^2
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