Posted by **suraj suwal** on Wednesday, September 14, 2011 at 12:38am.

A tennis ball with a speed of 25.9 m/s is

moving perpendicular to a wall. After striking

the wall, the ball rebounds in the opposite

direction with a speed of 21.3157 m/s.

If the ball is in contact with the wall for

0.0133 s, what is the average acceleration of

the ball while it is in contact with the wall?

- uta -
**SraJMcGin**, Wednesday, September 14, 2011 at 1:33am
We do not recognize uta as a School Subject. Look to the upper left for a choice.

Sra

- physics -
**drwls**, Wednesday, September 14, 2011 at 5:10am
Divide the velocity change by the time interval. Note that the bounceback velocity is negative.

Acceleration = [25.9 -(-21.3157)]/0.0133

= 3550 m/s^2

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