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September 20, 2014

September 20, 2014

Posted by **suraj suwal** on Wednesday, September 14, 2011 at 12:37am.

speed of 10 m/s from a height of 49 m above

the ground. At the same instant, a second

object is propelled vertically up from ground

level with a speed of 29 m/s .

At what height above the ground will the

two objects pass each other? The acceleration

of gravity is 9.8 m/s

2

.

Answer in units of m

- UTA -
**drwls**, Wednesday, September 14, 2011 at 5:06amFirst solve for the time when they are at the same height.

49 - 10 t - 4.9 t^2 = 29 t - 4.9 t^2

The t^2 terms cancel.

39t = 49

t = 1.2564 seconds

Then, use the height vs. time equation for either object for the vertical height at that time.

Y = 29t - 4.9 t^2 = 28.7 meters

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