3/2=40+y/4=
Please help
Multiply both sides by 4.
6 = 160 + y
Subtract 160 from both sides.
154 = y
y = -154
To solve the equation 3/2 = 40 + y/4, we will follow these steps:
Step 1: Simplify the equation.
Since 3/2 is a fraction, we need to convert 40 to a fraction as well. The fraction form of 40 is 40/1. So, the equation becomes:
3/2 = 40/1 + y/4
Step 2: Find a common denominator.
To add or subtract fractions, we need a common denominator. In this case, the common denominator for 2 and 4 is 4. So, we rewrite the equation with a common denominator:
3/2 = 40/1 + y/4
= 40/1 + y * (2/2) / 4
= 40/1 + 2y/4
Step 3: Add the fractions.
Now that we have a common denominator, we can add the fractions:
3/2 = (40 + 2y)/4
Step 4: Cross-multiply.
To eliminate the fractions, we can cross-multiply. This means multiplying the numerators of one fraction by the denominators of the other fraction:
3 * 4 = 2 * (40 + 2y)
Simplifying further, we get:
12 = 80 + 4y
Step 5: Solve for y.
To isolate the variable y, we need to move the constants to one side of the equation:
12 - 80 = 4y
-68 = 4y
Step 6: Divide both sides by 4.
Dividing both sides by 4 will further isolate y:
-68/4 = y
-17 = y
So, the solution to the equation 3/2 = 40 + y/4 is y = -17.