physics
posted by Nour .
You throw a ball straight down from an apartment balcony to the ground below. The ball has an initial velocity of 5.25 m/s, directed downward, and it hits the ground 1.94 s after it is released. Find the height of the balcony.

The vertical distance it falls in time t is:
Y = 5.25 t + (g/2) t^2
Plug in t = 1.94 s for your answer.
g = 9.8 m/s^2