Saturday

December 20, 2014

December 20, 2014

Posted by **Sydney** on Tuesday, September 13, 2011 at 10:05pm.

- Physics -
**drwls**, Tuesday, September 13, 2011 at 10:22pmFirst calculate the acceleration of the front of the train. When its velocity is V after traveling a distance X from a standing start,

V^2 = 2 a X, so

a = V^2 /(2X) = 1.198 m/s^2

When the last car passes the worker, the first car will have traveled 184 + 90 = 274 m

Use again V^2 = 2 a X, with the new value of X = 274. (a remains the same). This new V is the velocity of both the first and the last car at that time.

V^2 = 2*1.198*274

V = 25.6 m/s

- Physics -
**Anonymous**, Wednesday, September 19, 2012 at 4:46pmseriously bruh

**Answer this Question**

**Related Questions**

physics - An automobile and train move together along parallel paths at 28.8 m/s...

physics - An automobile and train move together along parallel paths at 20.3 m/s...

Physics - An automobile and train move together along parallel paths at 21.8 m/s...

physics - An automobile and train move together along parallel paths at 39.1 m/...

Physics - An automobile and train move together along parallel paths at 31.6 m/s...

physics - 2. A freight train traveling with a velocity of 18.0 m/s to the south ...

physics - A train is moving parallel to a highway with a constant speed of 16.0 ...

physics - A toy train is pushed forward and released at = 3.5 with a speed of 1....

maths - A person is cycling, parallel to a railway track, at a speed of 10 km/hr...

Physics - A train travels east at a speed of 50 m/s. A passenger is walking ...