Find the velocity in m/s of a dropped ball after 2.4 seconds in the air. Assume its initial velocity is zero.
Round answer to one decimal place.
To find the velocity of a dropped ball after a certain amount of time, we can use the equation for motion under gravity:
š£ = šš”
where š£ is the velocity, š is the acceleration due to gravity (which is approximately 9.8 m/sĀ² on Earth), and š” is the time in seconds.
In this case, the initial velocity is zero. So we can simply use the equation:
š£ = (9.8 m/sĀ²) Ć (2.4 s)
To calculate the velocity, we multiply the acceleration due to gravity, 9.8 m/sĀ², by the time, 2.4 seconds.
Calculating the result, we get:
š£ = 9.8 m/sĀ² Ć 2.4 s = 23.52 m/s
Rounding to one decimal place, the velocity of the dropped ball after 2.4 seconds is approximately 23.5 m/s.