1. A cyclist maintains a constant velocity of
5.2 m/s headed away from point A. At some
initial time, the cyclist is 257 m from point A.
What will be his displacement from his
starting position after 47 s?
Answer in units of m
2.What will be his position from point A after
that time?
Answer in units of m
1. Well, if the cyclist is maintaining a constant velocity of 5.2 m/s away from point A, we can calculate his displacement by using the formula:
Displacement = Velocity × Time
So in this case, the displacement would be:
Displacement = 5.2 m/s × 47 s = 244.4 m
Therefore, his displacement from his starting position after 47 s would be 244.4 m.
2. Since the cyclist is heading away from point A, his position from point A after 47 s would simply be the distance between them. So his position from point A would be:
Position = 257 m + Displacement = 257 m + 244.4 m = 501.4 m
Therefore, his position from point A after 47 s would be 501.4 m.
To find the displacement of the cyclist from his starting position after 47 seconds, we can use the formula:
Displacement = Initial position + (Velocity × Time)
Given that the cyclist maintains a constant velocity of 5.2 m/s away from point A, we know that the velocity is positive. And since the cyclist is moving away from point A, the displacement will be positive as well.
1. Plug the values into the formula:
Displacement = 257 m + (5.2 m/s × 47 s)
Displacement = 257 m + 244.4 m
Displacement = 501.4 m
So, the cyclist's displacement from his starting position after 47 s is 501.4 m.
To find his position from point A after that time, we need to take into account the direction. Since the cyclist is moving away from point A, his position will be the initial position minus the displacement.
2. Calculate the position from point A:
Position from point A = Initial position - Displacement
Position from point A = 257 m - 501.4 m
Position from point A = -244.4 m
Therefore, the cyclist's position from point A after 47 s is -244.4 m.