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December 22, 2014

December 22, 2014

Posted by **john** on Tuesday, September 13, 2011 at 11:11am.

(-9-sqrt-3)^2

- college algebra -
**bobpursley**, Tuesday, September 13, 2011 at 12:22pm[-9 -sqrt(-3)]^2

let me change that to i notation (i=sqrt-1)

[-9- i sqrt3]^2

Using FOIL

81+9isqsrt3 +9isqrt3+i^2*3

81+18i*sqrt3 -3

78+18i*sqrt3

remember i^2=-1

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