A 12kg blcok sits on a table. A 10 kg block sits on top of the 12kg block. What is the force the table exerts on the 12kg block.
Please explain any answer.
The table supports both.
F = m g = 22*9.8
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To determine the force that the table exerts on the 12kg block, we need to consider the forces acting on the system.
First, let's identify the relevant forces:
1. Weight of the 12kg block: This is the force exerted by gravity on the 12kg block. We can calculate this force using the equation: weight = mass * gravitational acceleration. The gravitational acceleration is approximately 9.8 m/s². Therefore, the weight of the 12kg block is: weight₁₂kg = 12kg * 9.8 m/s².
2. Weight of the 10kg block: Similar to the 12kg block, the weight of the 10kg block is calculated as: weight₁₀kg = 10kg * 9.8 m/s².
Now, let's analyze how these forces affect the 12kg block. Since the 10kg block is on top of the 12kg block, it exerts a downward force on the 12kg block due to its weight. This force is equal to weight₁₀kg.
According to Newton's third law, the table exerts an equal and opposite force on the 12kg block. This force counteracts the weight of both the 12kg and 10kg blocks.
Finally, to find the net force exerted by the table on the 12kg block, we can subtract the weight of the 10kg block from the weight of the 12kg block. This yields the force the table exerts on the 12kg block: F = weight₁₂kg - weight₁₀kg.
Substituting the values, we get:
F = (12kg * 9.8 m/s²) - (10kg * 9.8 m/s²).
F = 117.6 N - 98 N.
F = 19.6 N.
Therefore, the table exerts a force of 19.6 Newtons on the 12kg block.
To find the force that the table exerts on the 12 kg block, we need to analyze the forces acting on the system.
First, let's consider the 12 kg block. There are two forces acting on it: its weight (mg) directed downward and the force exerted by the table directed upward.
The weight of the 12 kg block can be calculated using the formula weight = mass × acceleration due to gravity, where the mass is 12 kg and the acceleration due to gravity is approximately 9.8 m/s². So the weight of the 12 kg block is 12 kg × 9.8 m/s² = 117.6 N.
Since the 12 kg block is at rest and there is no vertical acceleration, the net force must be zero. Therefore, the force exerted by the table on the 12 kg block must be equal in magnitude to the weight of the 12 kg block but in the opposite direction. Hence, the force exerted by the table on the 12 kg block is 117.6 N, directed upward.
Please note that the force exerted by the 10 kg block on the 12 kg block doesn't affect the calculation of the force exerted by the table, as it is an internal force within the system of the two blocks.