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April 19, 2014

April 19, 2014

Posted by **a** on Tuesday, September 13, 2011 at 12:16am.

2)How fast is the blue car going 10.4 seconds after it starts?

3)How far does the blue car travel before its brakes are applied to slow down?

4)What is the acceleration of the blue car once the brakes are applied?

- physics -
**Henry**, Wednesday, September 14, 2011 at 5:40pm1. V1 = Vo + at,

V1 = 0 + 4.6*4.4 = 20.24m/s.

2. V2 = V1 = 20.24m/s after 10.4s.

3. D = di + d2,

d1 = Vo*t + 0.5at^2,

d1 = 0 + 0.5*4.6*(4.4)^2 = 44.53m.

d2 = Vt = 20.24 * 8.5 = 172m.

D = 44.53 + 172 = 217m.

4. Ds = 247 - 217 = 30m = Stopping

distance.

a = (Vf^2 - Vo^2) / 2d,

a = (0 -(20.24)^2 / 60 = -6.83m/s^2.

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