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posted by Keisha on Monday, September 12, 2011 at 7:14pm.
What value of x would make these pentagons similar? Side A= 21 Side B= 3x-2 Side A'= 15 Side B'= 2x+1
Just set up the proportion (3x-2)/21 = (2+1)/15 cross-multiply and solve for x (I got x=17)
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