trig
posted by Piwokazi on .
Help find the general solution to:sin^2x3cosx+sinxcosx3sinx=0

sin^2x3cosx+sinxcosx3sinx=0
sin^2x  3sinx + sinxcosx  3cosx = 0
sinx(sinx  3) + cosx(sinx  3) = 0
(sinx  3)(sinx + cosx) = 0
sinx = 3 , which is not possible
or
sinx = cosx
sinx/cosx = 1
tanx = 1
x = 135° or 225° or in radians, 3π/4 , 5π/4
the period of tanx = 180° or π radians
general solution: = 3π/4 + kπ
or
x = 5π/4 + kπ , where k is an integer