Posted by Piwokazi on Monday, September 12, 2011 at 4:08pm.
Help find the general solution to:sin^2x-3cosx+sinxcosx-3sinx=0
- trig - Reiny, Monday, September 12, 2011 at 6:36pm
sin^2x - 3sinx + sinxcosx - 3cosx = 0
sinx(sinx - 3) + cosx(sinx - 3) = 0
(sinx - 3)(sinx + cosx) = 0
sinx = 3 , which is not possible
sinx = -cosx
sinx/cosx = -1
tanx = -1
x = 135° or 225° or in radians, 3π/4 , 5π/4
the period of tanx = 180° or π radians
general solution: = 3π/4 + kπ
x = 5π/4 + kπ , where k is an integer
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