Posted by **jennifer** on Monday, September 12, 2011 at 1:33pm.

a ball is thrown up with an initial velocity 20m/s. using g=10m/s2,

a) what's the maximum height it can reach.

b) what is the magnitude and direction of the ball's velocity 1 second after it is thrown.

c) what is the magnitude and direction of the ball's velocity 3 seconds after it is thrown

- physics -
**Henry**, Tuesday, September 13, 2011 at 6:34pm
a. h = (Vf^2 - Vo^2) / 2g,

h = (0 - (20)^2) / 20 = 20m.

b. Vf = Vo + gt,

Vf = 20 + (-10)*1 = 10m/s,up.

c. Vf = 20 + (-10)*3 = -10m/s,down.

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