physics
posted by jennifer on .
a ball is thrown up with an initial velocity 20m/s. using g=10m/s2,
a) what's the maximum height it can reach.
b) what is the magnitude and direction of the ball's velocity 1 second after it is thrown.
c) what is the magnitude and direction of the ball's velocity 3 seconds after it is thrown

a. h = (Vf^2  Vo^2) / 2g,
h = (0  (20)^2) / 20 = 20m.
b. Vf = Vo + gt,
Vf = 20 + (10)*1 = 10m/s,up.
c. Vf = 20 + (10)*3 = 10m/s,down.