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November 29, 2014

November 29, 2014

Posted by **Chris** on Monday, September 12, 2011 at 12:18am.

equation needed h=1/2 gt^2

Solve the equation for g; g=2h/t^2

Set height is 2 foot, dropped small object from 2ft, timed at 0.3 seconds. Calculate the gravity of the object.

Is this right?

2=1/2*9.8 t^2

t^2=2*2/9.8=0.40

t=0.40^

Answer =0.64 or is it 0.64*9.8=6.26, answer being 6.26

- science -
**Henry**, Tuesday, September 13, 2011 at 3:25pmg is the unknown in your Eq; you suppose to calculate it. T is 0.3s(given).

h = 0.5gt^2 = 2 Ft.

0.5g*(0.3)^2 = 2,

0.045g = 2,

g = 44.44 Ft/s^2.

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