How many milliliters of 1.5 M HCl must be transfered from a reagent bottle to provide 25 g HCl for a reaction? Answer in units of mL.
moles = grams/molar mass
You have grams and molar mass; solve for moles.
M = moles/L. You have M and moles, solve for L and convert to mL.
To solve this problem, you need to use the concentration of the HCl solution and the amount of HCl needed in order to calculate the volume of the solution that needs to be transferred.
First, convert the given mass of HCl (25 g) to moles. To do this, you need to know the molar mass of HCl, which is approximately 36.461 g/mol.
Moles of HCl = Mass of HCl / Molar mass of HCl
Moles of HCl = 25 g / 36.461 g/mol ≈ 0.686 mol
Next, use the balanced chemical equation for HCl to determine the stoichiometry. Since the stoichiometry of HCl is 1:1 (1 mol of HCl produces 1 mol of HCl), the moles of HCl needed are equal to the moles of HCl in the reagent bottle.
Now, use the concentration of the HCl solution (1.5 M) to calculate the volume of the solution needed.
Moles of HCl = Concentration of HCl x Volume of HCl solution
0.686 mol = 1.5 M x Volume of HCl solution
Rearrange the equation to solve for the volume of HCl solution:
Volume of HCl solution = Moles of HCl / Concentration of HCl
Volume of HCl solution = 0.686 mol / 1.5 M ≈ 0.457 L
Finally, convert the volume from liters to milliliters:
Volume of HCl solution = 0.457 L x 1000 mL/L = 457 mL
Therefore, you need to transfer approximately 457 mL of 1.5 M HCl solution from the reagent bottle in order to provide 25 g of HCl for the reaction.