It takes 58 mL of 0.124 M KOH to neutralize 34.5 mL of H2SO4 solution. What is the concentration of the H2SO4 solution? Answer in unites of moles/liter.
H2SO4 + 2KOH ==> K2SO4 + 2H2O
moles KOH used = M x L = ??
Convert moles KOH to moles H2SO4 using the coefficients in the balanced equation.
MH2SO4 = moles H2SO4/L HS2SO4. Solve for M H2SO4.
To find the concentration of the H2SO4 solution, we can use the concept of stoichiometry.
First, let's write down the balanced chemical equation for the neutralization reaction between KOH and H2SO4:
2 KOH + H2SO4 -> K2SO4 + 2 H2O
From the equation, we can see that 2 moles of KOH react with 1 mole of H2SO4. Therefore, the mole ratio between KOH and H2SO4 is 2:1.
Given that it took 58 mL of 0.124 M KOH to neutralize 34.5 mL of H2SO4, we can set up the following equation:
(58 mL) * (0.124 mol/L) = (34.5 mL) * (C mol/L)
Simplifying, we have:
(7.192 mol) = (34.5 mL) * (C mol/L)
Dividing both sides by 34.5 mL, we get:
C = (7.192 mol) / (34.5 mL)
Converting mL to liters, we have:
C = (7.192 mol) / (0.0345 L)
Thus, the concentration of the H2SO4 solution is approximately 208.93 mol/L.
To find the concentration of the H2SO4 solution, we can use the concept of stoichiometry.
First, let's write down the balanced chemical equation for the reaction between KOH and H2SO4:
2 KOH + H2SO4 -> K2SO4 + 2 H2O
From the equation, we can see that 2 moles of KOH react with 1 mole of H2SO4, meaning the ratio is 2:1.
Given that it takes 58 mL of 0.124 M KOH to neutralize 34.5 mL of H2SO4 solution, we can set up a proportion to solve for the concentration of the H2SO4 solution.
(0.124 M KOH) / 2 mol H2SO4 = (x M H2SO4) / 1 mol H2SO4
Where "x" represents the concentration of the H2SO4 solution.
Using the given volume of the KOH solution (58 mL), we can calculate the number of moles of KOH:
moles KOH = (volume KOH in liters) * (concentration of KOH in mol/L)
= (58 mL) * (1 L/1000 mL) * (0.124 mol/L)
= 0.007192 mol
Since the ratio of KOH to H2SO4 is 2:1, we know that the number of moles of H2SO4 is half that of KOH:
moles H2SO4 = 0.007192 mol / 2
= 0.003596 mol
Now that we know the number of moles of H2SO4 and the volume of the H2SO4 solution (34.5 mL), we can calculate the concentration of the H2SO4 solution:
concentration H2SO4 = (moles H2SO4) / (volume H2SO4 in liters)
= (0.003596 mol) / (34.5 mL) * (1 L/1000 mL)
= 0.000104 mol/L
Therefore, the concentration of the H2SO4 solution is 0.000104 mol/L or 104 mol/L.