Posted by **Hannah** on Sunday, September 11, 2011 at 6:25pm.

The radius of a niobium atom is 131 pm. How many niobium atoms would have to be laid side by side to span a distance of 1.4 mm??

I know that 10^9 is pm or is it -9??

- Math(Please help) -
**bobpursley**, Sunday, September 11, 2011 at 6:33pm
pm is a very small unit, smaller than a head lice. 1 m=10^9 pm, which is the same as 1pm is 10^-9 m

numberatoms*diatmeter atom=1.4mm

numberatoms*131pm=1.4mm

change both to m

numberatoms*131pm*1m/10^9pm)=1.4mm(1m/10^3mm)

number atoms= 1.4*10^9/(131*10^3)

number atoms=1.4 (10^6)/131=1.07*10^4

check that.

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