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September 18, 2014

September 18, 2014

Posted by **Bethany** on Sunday, September 11, 2011 at 5:08pm.

to the horizontal.

The acceleration of gravity is 9.8 m/s2 .

To throw a(n) 57.8 m pass, what must be

the initial speed of the ball?

Answer in units of m/s

- physics -
**bobpursley**, Sunday, September 11, 2011 at 5:36pmThink on this. to go L meters horizontally, it has to be in the air T seconds.

in the horizontal

L=vi*cosTheta*t-1/2 g t^2 where you solve for t in terms of the other unknowns (such as vi).

now in the vertical, the final position is the same as the initial position

vf=vi*sinTheta - g t

0=vi*sinTheta-g t put in the expression you found for t above, and solve for vi.

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