A force of 10 N is used to lift a 600-g ball from the ground to a height of 1.8 m, when it is let go. What is the speed of the ball when it is let go??

To find the speed of the ball when it is let go, we can use the principle of conservation of energy. The energy at the initial position (when the ball is on the ground) is converted into kinetic energy at the final position (when the ball is let go).

First, let's convert the mass of the ball from grams to kilograms. Since 1 kilogram (kg) equals 1000 grams (g), the mass of the ball is 600 g ÷ 1000 = 0.6 kg.

The potential energy of an object near the Earth's surface is given by the formula: potential energy = mass × acceleration due to gravity × height.
Here, the acceleration due to gravity is approximately 9.8 m/s^2.

Potential energy = 0.6 kg × 9.8 m/s^2 × 1.8 m = 10.44 J (Joules).

When the ball is let go, all its potential energy is converted into kinetic energy. The kinetic energy of an object is given by the formula: kinetic energy = (1/2) × mass × velocity^2.

We can now equate the potential energy to the kinetic energy:

10.44 J = (1/2) × 0.6 kg × velocity^2.

Simplifying the equation, we get:

(1/2) × 0.6 kg × velocity^2 = 10.44 J.

Now, rearranging the equation to solve for the velocity:

velocity^2 = (10.44 J) / [(1/2) × 0.6 kg].

velocity^2 = 34.8 m^2/s^2.

Taking the square root of both sides of the equation:

velocity = √(34.8) m/s.

Therefore, the speed of the ball, when it is let go, is approximately 5.9 m/s.