Posted by **Raymond** on Sunday, September 11, 2011 at 3:29pm.

How would you solve for X if X was the hypotenuse of a 45-45-90 triangle and the other two sides were Square Root of 11?

- Math -
**MathMate**, Sunday, September 11, 2011 at 3:44pm
Use Pythagoras theorem:

hypotenuse² = side1²+side2²l

=(√11)²+(√11)²

= 11 + 11

= 22

Therefore

hypotenuse = √22

- Math -
**Raymond**, Sunday, September 11, 2011 at 3:49pm
Thank you very much! I thought it was 2 Square Roots of 11. You saved me.

- Math -
**MathMate**, Sunday, September 11, 2011 at 7:14pm
The method I have shown above is more general, and applies to any right-triangle.

For a 45-45-90 triangle, you were close with the answer. A short-cut would be to multiply each side by √2, which makes:

√2 * √11

=√22.

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