Monday

March 30, 2015

March 30, 2015

Posted by **Zach** on Sunday, September 11, 2011 at 10:31am.

- Math -
**Henry**, Monday, September 12, 2011 at 6:38pm1c. = 3^0,

3c = 3^1,

9c. = 3^2,

27c = #^3.

So we have base 3 numerals.

A = 3^(n-1). A = Amount in cents @ nth year.

a. 3^(n-1) = 100,000 cents.

(n-1)Log3 = Log100,000,

n-1 = Log100,000 / Log3 = 10.5,

n = 11.5 years of age.

b. A = 3^(18-1),

A = 3^17 = 129,140,163 cents,

A = $1,291,401.63.

**Answer this Question**

**Related Questions**

dividing a polynomial by a polynomial - (-6v^2 - 4 + 9v +v^3)/ (v - 4)i am just...

Maths - Grandpa places money in an account on your first birthday and will place...

Algebra 2 - Question is about Step Functions:(between" " are all floor functions...

java/programming - ask the user to enter his or her birthday in the MM/DD/YYYY ...

math - Chris received $1 on his first birthday,$3 on his second birthday,$6 on ...

Math(Please Check) - Problem: 4x/(x+2)-8/(x-1) What I Got: 4x^2-4x-16/(x+2)(x+1...

English - Hi Miss Sue, Here is the final draft can you check it for me? Thank ...

Finance - 8. Assume you just turned 28. You want to accumulate $3.5 million by ...

math - A woman buys a $ 78 necklace at a jewelry store. She gives the jeweler a ...

math - 1. First of all, pick the number of times a week that you eat chocolate. ...