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December 17, 2014

December 17, 2014

Posted by **Zach** on Sunday, September 11, 2011 at 10:31am.

- Math -
**Henry**, Monday, September 12, 2011 at 6:38pm1c. = 3^0,

3c = 3^1,

9c. = 3^2,

27c = #^3.

So we have base 3 numerals.

A = 3^(n-1). A = Amount in cents @ nth year.

a. 3^(n-1) = 100,000 cents.

(n-1)Log3 = Log100,000,

n-1 = Log100,000 / Log3 = 10.5,

n = 11.5 years of age.

b. A = 3^(18-1),

A = 3^17 = 129,140,163 cents,

A = $1,291,401.63.

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