Posted by Zach on Sunday, September 11, 2011 at 10:31am.
1c. = 3^0,
3c = 3^1,
9c. = 3^2,
27c = #^3.
So we have base 3 numerals.
A = 3^(n-1). A = Amount in cents @ nth year.
a. 3^(n-1) = 100,000 cents.
(n-1)Log3 = Log100,000,
n-1 = Log100,000 / Log3 = 10.5,
n = 11.5 years of age.
b. A = 3^(18-1),
A = 3^17 = 129,140,163 cents,
A = $1,291,401.63.