Posted by **Catherine** on Saturday, September 10, 2011 at 9:19pm.

A tension test was performed on a steel specimen having an original diameter of 12.5 mm and gauge length

of 50 mm. Using the data listed in the table, plot the stressâ€“strain diagram, and determine approximately the

modulus of toughness. Use a scale of 20 mm-50 MPa and 20 mm = 0.05 mm/mm.

Load (kN)

0

11.1

31.9

37.8

40.9

43.6

53.4

62.3

64.5

62.3

58.8

Elongation (mm)

0

0.0175

0.0600

0.1020

0.1650

0.2490

1.0160

3.0480

6.3500

8.8900

11.9380

I know that I have to use the equations sigma=(P/A) and epsilon=(dL/L) to get the points for stress and strain... but how do I get the values for the equations? I tried to get the stress with the second values of the table:

sigma=(11.1e3 Pa)/(pi*(0.0175e3m)^2)

I get 11.54 and it is supposed to be 90.45 MPa. How do I do these?

- Mechanics -
**bobpursley**, Saturday, September 10, 2011 at 9:25pm
sigma is in fact Pressure, which is force/area. you are given force, compute area from the diameter.

epsilon is change of length divided by length. You are given deltaL (elongation). L was given as 50mm.

Surely you can calculate delta L /L

For each data point given, calculate those two quantities (sigma, deltaL/L), and plot the graph

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