posted by Jason on .
A rocket starts from rest and moves upward from the surface of the earth. For the first 10s of its motion, the vertical acceleration of the rocket is given by a_y =( 2.70m/s^3)t, where the +y-direction is upward.
1) What is the height of the rocket above the surface of the earth at t = 10 s?
2) What is the speed of the rocket when it is 345 m above the surface of the earth?