Posted by **Rebekah** on Saturday, September 10, 2011 at 4:59pm.

A car moving with constant acceleration covered the distance between two points 60.0 m apart in 6.00 s. Its speed as it passed the second point was 15.0 m/s. (a) What was the speed at the first point? (b) What was the magnitude of the acceleration? (c) At what prior distance from the first point was the car at rest? (d) Graph x versus t and v versus t for the car, from rest (t = 0).

- physics -
**bobpursley**, Saturday, September 10, 2011 at 5:56pm
d= vi*t+1/2 a t^2

60=6Vi+18a

but vf=vi+at

15=vi+6a

so you have two equations, two unknowns, solve. Multiply the second equation by 3, and subtract it frm the first is easy way.

## Answer this Question

## Related Questions

- chaitanya - A car moving with constant acceleration covers the distance between ...
- physics - a car moving with constant acceleration covers a distance between two ...
- physics - A car moving with a constant acceleration covers the distance between ...
- physics - A car moving with a constant acceleration covers the distance between ...
- Physics - A car moving with a constant acceleration covers the distance between ...
- physics - An antelope moving with constant acceleration covers the distance ...
- General Physics I - An antelope moving with constant acceleration covers the ...
- Physics - An antelope moving with constant acceleration covers the distance ...
- physics college - An antelope moving with constant acceleration covers the ...
- science - A car moving with constant acceleration covers the distance between ...

More Related Questions