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July 30, 2014

July 30, 2014

Posted by **Ram** on Saturday, September 10, 2011 at 2:42am.

Consider the following function.

h(x) = (tan(x)-x)/x^3

(a) Evaluate h(x) for the following values of x. (Give your answer correct to six decimal places.)

x =

a) 1

b) 0.5

c) 0.1

d) 0.05

e) 0.01

f) 0.005

what is f(x)

(b) Guess the value of the limit of h(x) as x approaches 0. (If it does not exist, enter NONE.)

- calculus -
**Mgraph**, Saturday, September 10, 2011 at 7:48amWe want to "guess" that limh(x)=1/3 if x->0

h(1)=(tan(1)-1)/1^3=0.557408

h(0.1)=0.334672

h(0.005)=(tan(0.005)-0.005)/0.005^3=0.333342

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