Posted by **Dee** on Friday, September 9, 2011 at 1:26am.

Find the equation of the circle that satisfies the given conditions.

Center at the origin and passes through (7, 9)

130 = ?

- Math -
**Reiny**, Friday, September 9, 2011 at 8:48am
any circle with centre at the origin has equation

x^2 + y^2 = r^2

simply sub in the point(7,9) to find the value of r^2

- geometry -
**liz**, Monday, November 7, 2016 at 10:13am
A circle is centered at the point (5, -4) and passes through the point (-3, 2).

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