Posted by Dee on Friday, September 9, 2011 at 1:26am.
Find the equation of the circle that satisfies the given conditions.
Center at the origin and passes through (7, 9)
130 = ?

Math  Reiny, Friday, September 9, 2011 at 8:48am
any circle with centre at the origin has equation
x^2 + y^2 = r^2
simply sub in the point(7,9) to find the value of r^2

geometry  liz, Monday, November 7, 2016 at 10:13am
A circle is centered at the point (5, 4) and passes through the point (3, 2).
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