The ball is thrown upward with a speed of 38.0m/s from the top of a building 240 meters tall. How long will it take for this ball to reach the highest point?

6.3 (ish)seconds !

11.6

33.8

33.8

3.88

To determine how long it will take for the ball to reach the highest point, we need to use the principles of physics, specifically the law of motion and kinematics equations.

First, let's define the variables:
- Initial velocity (u) = 38.0 m/s (upward)
- Final velocity (v) = 0 m/s (at the highest point)
- Acceleration (a) = -9.8 m/s² (due to gravity, acting downward)
- Initial displacement (s) = 240 m (upward)
- Time taken (t) = unknown

Using the kinematic equation:

v = u + at

Since the ball is thrown upward, the final velocity at the highest point will be zero. Thus, we can rearrange the equation as follows:

0 = 38.0 m/s + (-9.8 m/s²) * t

Solving for time (t):

-38.0 m/s = -9.8 m/s² * t

Dividing both sides of the equation by -9.8 m/s²:

t = (-38.0 m/s) / (-9.8 m/s²)

t ≈ 3.88 s

Therefore, it will take approximately 3.88 seconds for the ball to reach the highest point.