Find an expression for the function f(x) whose graph is given by the top half of the circle(x-3)^2 + y^2 = 121.
f(x) = ????
To find an expression for the function f(x) whose graph represents the top half of the circle given by (x - 3)^2 + y^2 = 121, we can rearrange the equation to solve for y.
Start by subtracting (x - 3)^2 from both sides:
y^2 = 121 - (x - 3)^2
Take the square root of both sides to isolate y:
y = ±√(121 - (x - 3)^2)
Now, since we want the graph of f(x) to only represent the top half of the circle, we only want the positive square root. Thus, the expression for the function f(x) is:
f(x) = √(121 - (x - 3)^2)