Posted by **Sahil Patel** on Wednesday, September 7, 2011 at 6:42pm.

A baseball player releases a baseball at the height of 7 feet above the ground with an initial vertical velocity of 54 feet per second. How long will it take the ball to reach the ground?

- algebra -
**Henry**, Saturday, September 10, 2011 at 3:06pm
Vf^2 = Vo^2 + 2gd,

d = (Vf^2 - Vo^2) / 2g,

d = 7 + (0 - (54)^2) / -64 = 52.56 Ft.

= Distance above ground.

Vf = Vo + gt,

t(up) = (Vf - Vo) / g,

t(up) = (0 - 54) / -32 = 1.69s.

d = Vo*t + 0.5gt^2 = 52.56 Ft.

0 + 0.5*32t = 52.56,

16t = 52.56,

t(down) = 3.29s.

T = t(up) + t(down) = 1.69 + 3.29 = 4.98s = Time to reach ground.

- algebra -
**Henry**, Saturday, September 10, 2011 at 3:19pm
Correction:

0 + 0.5*32t^2 = 52.56,

16t^2 = 52.56,

t^2 = 3.29,

t(down) = 1.81s.

T = t(up) + t(down) = 1.69 + 1.81 = 3.50s. = Time to reach ground.

## Answer This Question

## Related Questions

- math - a baseball is hit with an initial velocity of 75 feet per second from the...
- Algebra - A baseball is hit at a point 2 feet above the ground at a velocity of...
- Algebra 2 - a person throws a baseball into the air with an initial vertical ...
- Algebra - A baseball player hits a foul ball straight up in the air from a ...
- Algebra - A baseball player hits a baseball into the air with an initial ...
- college algebra - Isn't this a plug and chug? I will be happy to critique your ...
- Alegra 2 - A baseball is hit at a point of 3 feet above ground at a velocity of ...
- math - A robotic basketball player tosses a ball upward from a height of 7 feet...
- Pre-Cal - A baseball player throws baseball at a velocity 139ft per second at an...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...

More Related Questions