Posted by Sahil Patel on Wednesday, September 7, 2011 at 6:42pm.
A baseball player releases a baseball at the height of 7 feet above the ground with an initial vertical velocity of 54 feet per second. How long will it take the ball to reach the ground?
- algebra - Henry, Saturday, September 10, 2011 at 3:06pm
Vf^2 = Vo^2 + 2gd,
d = (Vf^2 - Vo^2) / 2g,
d = 7 + (0 - (54)^2) / -64 = 52.56 Ft.
= Distance above ground.
Vf = Vo + gt,
t(up) = (Vf - Vo) / g,
t(up) = (0 - 54) / -32 = 1.69s.
d = Vo*t + 0.5gt^2 = 52.56 Ft.
0 + 0.5*32t = 52.56,
16t = 52.56,
t(down) = 3.29s.
T = t(up) + t(down) = 1.69 + 3.29 = 4.98s = Time to reach ground.
- algebra - Henry, Saturday, September 10, 2011 at 3:19pm
0 + 0.5*32t^2 = 52.56,
16t^2 = 52.56,
t^2 = 3.29,
t(down) = 1.81s.
T = t(up) + t(down) = 1.69 + 1.81 = 3.50s. = Time to reach ground.
Answer this Question
- math - a baseball is hit with an initial velocity of 75 feet per second from the...
- Algebra - A baseball player hits a baseball into the air with an initial ...
- Algebra - A baseball is hit at a point 2 feet above the ground at a velocity of...
- Algebra 2 - a person throws a baseball into the air with an initial vertical ...
- Alegra 2 - A baseball is hit at a point of 3 feet above ground at a velocity of ...
- college algebra - Isn't this a plug and chug? I will be happy to critique your ...
- math - Baseball Nick throws a baseball upward with an initial velocity of 60 ...
- math - A robotic basketball player tosses a ball upward from a height of 7 feet...
- Alg 1 - A baseball player hit a ball with an upward velocity of 46 ft/s. Its ...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...