Posted by steph on Wednesday, September 7, 2011 at 12:17pm.
Thus, oxygen must the the limiting reagent.
C + O2 ==> CO2
78.0 g O2 to start
remaining is 10.8; therefore,
78.0-10.8 = 67.2 g oxygen consumed.
That is 67.2/32 = ?moles.
?mols O2 x (1 mole CO2/1 mole O2) = ?moles CO2.
grams CO2 = moles CO2 x molar mass CO2.
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