Posted by **Hannah** on Tuesday, September 6, 2011 at 11:58pm.

At the heighest point on earth, the distance to the center of the earth is approximately equal to 1.0014 times the radius of the earth. What would be in N/kg the magnitude of the gravitational field (g) due to the earth at that position? Assume 9.8 N/kg for g at the surface of the earth.

## Answer This Question

## Related Questions

- Physics - When out in space in International Space Station (ISS), Astronauts ...
- Physics: Astronauts and space - When out in space in International Space Station...
- Physics - When out in space in International Space Station (ISS), Astronauts ...
- Physics - The density of the Earth, at any distance r from its center, is ...
- physics - Find the gravitational acceleration if a spaceship at a distance equal...
- physics - Find the distance (measured in earth radii, RE) from the center of the...
- Physics - The Earth has an electric field with magnitude roughly 100 N/C at its ...
- Physics - A spaceship of mass m travels from the Earth to the Moon along a line ...
- Calculus Physics - Imagine a spaceship on its way to the moon from the earth. ...
- physics - A spaceship of mass m travels from the Earth to the Moon along a line ...

More Related Questions