Posted by Sheila on .
Please helpI'm stuck really bad
Thank you for any help you can provide
What are the roots of the equation x^2 4x + 3 = 0
x^2  4x = 3
x^2 +2(2)x + 2^2 = 3 = 2^2
x^2 + 4x + 4 = 1
(x + 2)^2 = 1
qrt (x+2)^2 = sqrt 1
x+2 = plus or minus 1
therefore x=1
x=3 roots are 1 and 3

PreCalcPlease check my answer 
bobpursley,
You did this about the most difficult way.
Consider:
x^24x3=0
(x1)(x3)=0
x= 1, or 3 
PreCalcPlease check my answer 
Damon,
x^2 4x + 3 = 0
factor
(x3)(x1) = 0
x = 3 or x = 1
or complete the square as you tried
x^2 4 x = 3 note sign change of 3
x^2  4 x + 4 = 3 +4 = 1
(x2)^2 = 1
x = 2 +/ 1
x = 1 or x = 3 
PreCalcPlease check my answer 
ALISON,
I believe you are trying to factor the polynomial.
so x^2 4x+3
(x1)(x3) =0
x= 1,3 
PreCalcPlease check my answer 
Damon,
Alison, I am sure Sheila was trying to do it by completing the square. Note taking half of the coef. of x and squaring it. Factoring is too easy.

PreCalcPlease check my answer 
Sheila,
I did do it the long wayyou way is much simpler Thank you all