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September 18, 2014

September 18, 2014

Posted by **Sheila** on Tuesday, September 6, 2011 at 8:12pm.

Thank you for any help you can provide

What are the roots of the equation x^2 -4x + 3 = 0

x^2 - 4x = 3

x^2 +2(-2)x + -2^2 = -3 = -2^2

x^2 + -4x + 4 = 1

(x + -2)^2 = 1

qrt (x+-2)^2 = sqrt 1

x+-2 = plus or minus 1

therefore x=1

x=3 roots are 1 and 3

- Pre-Calc-Please check my answer -
**bobpursley**, Tuesday, September 6, 2011 at 8:14pmYou did this about the most difficult way.

Consider:

x^2-4x-3=0

(x-1)(x-3)=0

x= 1, or 3

- Pre-Calc-Please check my answer -
**Damon**, Tuesday, September 6, 2011 at 8:16pmx^2 -4x + 3 = 0

factor

(x-3)(x-1) = 0

x = 3 or x = 1

or complete the square as you tried

x^2 -4 x = -3 note sign change of 3

x^2 - 4 x + 4 = -3 +4 = 1

(x-2)^2 = 1

x = 2 +/- 1

x = 1 or x = 3

- Pre-Calc-Please check my answer -
**ALISON**, Tuesday, September 6, 2011 at 8:16pmI believe you are trying to factor the polynomial.

so x^2 -4x+3

(x-1)(x-3) =0

x= 1,3

- Pre-Calc-Please check my answer -
**Damon**, Tuesday, September 6, 2011 at 8:19pmAlison, I am sure Sheila was trying to do it by completing the square. Note taking half of the coef. of x and squaring it. Factoring is too easy.

- Pre-Calc-Please check my answer -
**Sheila**, Tuesday, September 6, 2011 at 8:21pmI did do it the long way-you way is much simpler Thank you all

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