need to know how to solve the following....
a gas filled weather balloon floating in the atomsphere has an initial volume of 850 L. The balloon rises to a region where the pressure is 56 kPa and its volume expands to 1700 L. If the temperature remains the same, what was the initial pressure on the weaher balloon?
Use Boyles law
P1V1 = P2V2
Answer 112 kPa
(850)(x)=(1700)(56) <--- Equation
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature remains constant.
Boyle's Law can be expressed mathematically as P1 * V1 = P2 * V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
In this case, we are given:
- Initial volume (V1) = 850 L
- Final volume (V2) = 1700 L
- Final pressure (P2) = 56 kPa
We need to find the initial pressure (P1).
We can substitute the known values into the equation and solve for P1 as follows:
P1 * V1 = P2 * V2
P1 = (P2 * V2) / V1
= (56 kPa * 1700 L) / 850 L
= 112 kPa
Therefore, the initial pressure on the weather balloon was 112 kPa.