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December 18, 2014

December 18, 2014

Posted by **Sheila** on Tuesday, September 6, 2011 at 5:05pm.

What are the roots of the equation x^2 - 4x + 3 = 0

I think I was suppose to use b^2 - 4ac

so it would be -4 - (-4)*1*3 = 12 so the roots would be 12 and -12

Thank you for any help you can provide

- Pre-Calc/TrigPlease check this answer I redid -
**Sheila**, Tuesday, September 6, 2011 at 5:31pmx^2 -4x + 3 = 0

x^2 - 4x = 3

x^2 +2(-2)x + -2^2 = -3 = -2^2

x^2 + -4x + 4 = 1

(x + -2)^2 = 1

qrt (x+-2)^2 = sqrt 1

x+-2 = plus or minus 1

therefore x=1

x=3 roots are 1 and 3

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