Monday

March 30, 2015

March 30, 2015

Posted by **Sheila** on Tuesday, September 6, 2011 at 5:05pm.

What are the roots of the equation x^2 - 4x + 3 = 0

I think I was suppose to use b^2 - 4ac

so it would be -4 - (-4)*1*3 = 12 so the roots would be 12 and -12

Thank you for any help you can provide

- Pre-Calc/TrigPlease check this answer I redid -
**Sheila**, Tuesday, September 6, 2011 at 5:31pmx^2 -4x + 3 = 0

x^2 - 4x = 3

x^2 +2(-2)x + -2^2 = -3 = -2^2

x^2 + -4x + 4 = 1

(x + -2)^2 = 1

qrt (x+-2)^2 = sqrt 1

x+-2 = plus or minus 1

therefore x=1

x=3 roots are 1 and 3

**Answer this Question**

**Related Questions**

Pre-Calc-Please check my answer - Please help-I'm stuck really bad Thank you ...

Pre-Calculus/Trig Check please and help - Could someone please check the first ...

Pre-Calc/Trig - Please check the first and help with the second-thank you Find ...

Pre-trig/Calc - Please help me. Use Descartes' rule of signs to describe the ...

Pre-Calc/Trig... - Helpp needed, this is sort of confusing me. Describe the ...

Pre-Calc/Trig... - Use the discriminant to determine the nature of the roots. 1...

Pre-Calc/Trig - Use Descartes' rule of signs to describe the roots of the ...

Pre-Calc - I know about Descartes Rule but I don't really get how to figure this...

Trig/Pre-Calc - Could someone please help me on this problem. I'm really ...

Math - Can someone please explain this problem to me? I would appreciate it very...