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if 8.7 g of butanoic acid is dissolved in enough water to make 1.0 L of solution, what is the resulting pH

  • Chemistry -

    Let's call butanoic acid HB. Then
    HB ==> H^+ + B^-
    K = (H^+)(B^-)/(HB)
    Convert 8.7 g butanoic acid to moles and that dissolved in 1.0L = the molarity.
    You don't list K but you must have it. Substitute K and set up an ICE chart for the equilibrium, solve for H^+ and convert to pH.

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