A child traveling 5m/s on a sled passes her younger brother.if her average acceleration on the sledding hill is 2m/s,how fast is she traveling when she passes her older brother 4s later.
Vf = Vo + at,
Vf = 5 + 2*4 = 13m/s.
Well, isn't that a slippery situation! It seems like this girl and her sled have a need for speed. Let's break it down.
The girl's initial speed is 5 m/s, and her average acceleration is 2 m/s. So, after 4 seconds, we can calculate her final speed using the formula:
Final speed = Initial speed + (Acceleration x Time)
Plugging in the values, we get:
Final speed = 5 m/s + (2 m/s x 4s)
Final speed = 5 m/s + 8 m/s
Final speed = 13 m/s
Wow, looks like she really zoomed past her older brother! But hey, let's hope she doesn't speed too much and get herself a speeding ticket on that sled!
To find the child's final velocity when she passes her older brother, we can use the equation:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given data:
Initial velocity (u) = 5 m/s
Acceleration (a) = 2 m/s^2
Time (t) = 4 s
By substituting the values into the equation, we get:
v = 5 m/s + (2 m/s^2)(4 s)
v = 5 m/s + 8 m/s
v = 13 m/s
Therefore, the child is traveling at a speed of 13 m/s when she passes her older brother.
To find the speed at which the child is traveling when she passes her older brother, we need to calculate her final velocity after a time interval of 4 seconds.
The initial velocity of the child is given as 5 m/s, and the average acceleration is given as 2 m/s.
We can use the formula of motion:
v = u + at
Where:
v = final velocity
u = initial velocity
a = average acceleration
t = time interval
Plugging in the given values into the formula, we have:
v = 5 m/s + (2 m/s^2)(4 s)
First, we calculate the acceleration multiplied by the time interval:
(2 m/s^2)(4 s) = 8 m/s
Then, we add this value to the initial velocity:
v = 5 m/s + 8 m/s
v = 13 m/s
Therefore, the child is traveling at a speed of 13 m/s when she passes her older brother.