Posted by ninzyy on .
I'm going crazy please help me out
part 1 of 2 Determine the mass of anhydrous copper(II) sulfate that must be used to prepare 250 mL of 2.01 M CuSO4(aq). Which i found to be 80.204g
part 2 of 2
Determine the mass of CuSO4.5H2O that must be used to prepare 250 mL of 2.01 M CuSO4(aq).
Na3AsO4 is a salt of a weak base that can accept more than one proton. If 30.2 g of Na3AsO4 is dissolved in water to make 250 mL of solution, how many moles of sodium cations are in the solution?
Answer in moles
1. 80.204 is ok except you are not allowed that many significant figures.
2. This one is done just like #1 but instead of molar mass being 159.61 it is 159.61+(5*80)= ?? or about that. YOu need to check that out.
3. moles Na3AsO4 = grams/molar mass.
moles Na^+ = 3x that. The amount of water in which it is places makes no difference.
of 1.79 M CuSO4(aq).