Posted by Amy on .
sketch + describe graph of the curve parametrized by:
x=13cos^(2)t
y=2+4sin^(2)t
infinity less than t less than infinity
how would i go about solving this.
i know that usually i can solve for t and than plug that in. But for this, i tried using cos^2 + sin^2 = 1... but i'm stuck

MATH help 
Mgraph,
cos^2(t)=(1x)/3
sin^2(t)=(y+2)/4
Add two equations
1=(1x)/3+(y+2)/4
12=44x+3y+6
y=(4/3)x+2/3 
MATH help 
Amy,
i don't really understand parametrized curves. but isn't y=(4/3)x +(2/3) a straight line. So, it doesn't have to be a curve?

MATH help 
Mgraph,
Straight line is a special case of the curve just like the natural numbers are a special case of integers