Posted by Amy on Monday, September 5, 2011 at 6:09pm.
sketch + describe graph of the curve parametrized by:
x=13cos^(2)t
y=2+4sin^(2)t
infinity less than t less than infinity
how would i go about solving this.
i know that usually i can solve for t and than plug that in. But for this, i tried using cos^2 + sin^2 = 1... but i'm stuck

MATH help  Mgraph, Monday, September 5, 2011 at 7:33pm
cos^2(t)=(1x)/3
sin^2(t)=(y+2)/4
Add two equations
1=(1x)/3+(y+2)/4
12=44x+3y+6
y=(4/3)x+2/3

MATH help  Amy, Monday, September 5, 2011 at 8:09pm
i don't really understand parametrized curves. but isn't y=(4/3)x +(2/3) a straight line. So, it doesn't have to be a curve?

MATH help  Mgraph, Monday, September 5, 2011 at 9:49pm
Straight line is a special case of the curve just like the natural numbers are a special case of integers
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