Posted by **Amy** on Monday, September 5, 2011 at 6:09pm.

sketch + describe graph of the curve parametrized by:

x=1-3cos^(2)t

y=-2+4sin^(2)t

-infinity less than t less than infinity

how would i go about solving this.

i know that usually i can solve for t and than plug that in. But for this, i tried using cos^2 + sin^2 = 1... but i'm stuck

- MATH help -
**Mgraph**, Monday, September 5, 2011 at 7:33pm
cos^2(t)=(1-x)/3

sin^2(t)=(y+2)/4

Add two equations

1=(1-x)/3+(y+2)/4

12=4-4x+3y+6

y=(4/3)x+2/3

- MATH help -
**Amy**, Monday, September 5, 2011 at 8:09pm
i don't really understand parametrized curves. but isn't y=(4/3)x +(2/3) a straight line. So, it doesn't have to be a curve?

- MATH help -
**Mgraph**, Monday, September 5, 2011 at 9:49pm
Straight line is a special case of the curve just like the natural numbers are a special case of integers

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