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October 20, 2014

October 20, 2014

Posted by **Jeremy** on Monday, September 5, 2011 at 6:02pm.

- geometry -
**Mgraph**, Monday, September 5, 2011 at 7:26pmLet R(x1,y1), S(x2,y2), then

x1=(2*2+8)/3=4, y1=(2*3+(-9))/3=-1

x2=(2+2*8)/3=6, y2=(3+2*(-9))/3=-5

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