Physics
posted by Natalie on .
From t = 0 to t = 5.00 min, a man stands still, and from t = 5.00 min to t = 10.0 min, he walks briskly in a straight line at a constant speed of 2.3 m/s.
(a) What is his average velocity vavg in the interval 2.000 min to 7.90 min?
I found this to be 1.15 m/s
(b) What is his average acceleration aavg in the interval 2.00 min to 7.90 min?
How do I go about solving this?
Would I do 1.15m/s divided by 354 seconds?

actually should I do 2.3 m/s divided by 343 seconds to get .00599 m/s^2?