Homework Help: Physics

Posted by Natalie on Monday, September 5, 2011 at 3:57pm.

From t = 0 to t = 5.00 min, a man stands still, and from t = 5.00 min to t = 10.0 min, he walks briskly in a straight line at a constant speed of 2.3 m/s.
(a) What is his average velocity vavg in the interval 2.000 min to 7.90 min?
I found this to be 1.15 m/s

(b) What is his average acceleration aavg in the interval 2.00 min to 7.90 min?
How do I go about solving this?
Would I do 1.15m/s divided by 354 seconds?

Physics - Natalie, Monday, September 5, 2011 at 4:16pm
actually should I do 2.3 m/s divided by 343 seconds to get .00599 m/s^2?

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