Posted by **Amber** on Monday, September 5, 2011 at 12:39pm.

Find the intercepts of the graph of x^2 + y^2 + 4xy - 2x + 7y = 8

- pre-calculus -
**Reiny**, Monday, September 5, 2011 at 12:49pm
for x-intercept , let y = 0

x^2 + 0 + 0 - 2x + 0 = 8

x^2 - 2x - 8 = 0

(x-4)(x+2) = 0

x = 4 or x = -2

so the x-intercepts are (4,0), and (-2,0)

for the y-intercepts, let x = 0

0+y^2 + 0 - 0 + 7y =8

..

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you finish it, let me know what you get.

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