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November 26, 2014

November 26, 2014

Posted by **babygirl** on Monday, September 5, 2011 at 7:38am.

z-(2z-[3z-(4z-5z)-6z0-7z]-8z

- algebra -
**Reiny**, Monday, September 5, 2011 at 7:51amCheck for a typo:

I will assume that -6z0 is supposed to be -6z

You also have one ( bracket which is not closed, I will assume it closes after the -8z .

z-(2z-[3z-(4z-5z)-6z-7z]-8z)

= z-(2z-[3z-4z+5z-6z-7z]-8z)

= z - (2z -[-9z] -8z)

= z - (2z+9z-8z)

= z - (3z)

= -2z

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