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November 24, 2014

November 24, 2014

Posted by **diviya** on Monday, September 5, 2011 at 7:06am.

- mathematics -
**Reiny**, Monday, September 5, 2011 at 7:26amI don't know how many trig ratios of half-angles you have developed or know but here is a page where many of them are done.

http://www.intmath.com/analytic-trigonometry/4-half-angle-formulas.php

about 2/3 of the way down you should find

tan [(A+B)/2) = (sinA +sinB)/(cosA + cosB)

= x/y

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