Posted by **Cady** on Monday, September 5, 2011 at 2:48am.

Please help me calculate these integrals.

Suppose that Int 0->1 f(t)dt=11 . Calculate each of the following.

A. int0->0.25 f(4t)dt=

B. int0->0.25 f(1−4t)dt=

C. int0.25->0.375 f(3−8t)dt=

- Calculus -
**MathMate**, Monday, September 5, 2011 at 7:24am
Try substitution:

u=4t

du=4dt, or

dt=(1/4)du

then

∫f(4t)dt [0,0.25]

=∫f(u)(1/4)du [0,4*0.25]

=(1/4)∫f(u)du [0,1]

=(1/4)*11

=11/4

The other problems should work similarly.

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