Posted by Lola on .
Answer check: I got 1.66 x 10^3 g O2
A steel cylinder contains 98.0 moles of oxygen gas at a temperature of 38 degrees C and a pressure of 740 torr. After some of the oxygen gas has been used, the pressure is reduced to 332 toor at a temperature of 24 degrees C. What mass of oxygen gas is removed from the cylinder?
Use PV = nRT and solve for the NEW number moles from the second set of conditions and subtract from the original moles to give you moles oxygen removed. Then n = grams/molar mass and solve for grams.