Homework Help: Chemistry

Posted by Lola on Monday, September 5, 2011 at 1:31am.

Answer check: I got 1.66 x 10^3 g O2

A steel cylinder contains 98.0 moles of oxygen gas at a temperature of 38 degrees C and a pressure of 740 torr. After some of the oxygen gas has been used, the pressure is reduced to 332 toor at a temperature of 24 degrees C. What mass of oxygen gas is removed from the cylinder?

Chemistry - DrBob222, Monday, September 5, 2011 at 1:58am
Use PV = nRT and solve for the NEW number moles from the second set of conditions and subtract from the original moles to give you moles oxygen removed. Then n = grams/molar mass and solve for grams.

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