posted by Dwight on .
The x vector component of a displacement vector has a magnitude of 104 m and points along the negative x axis. The y vector component has a magnitude of 185 m and points along the negative y axis.
(a) Find the magnitude of .
(b) Find the direction of .
_________° counterclockwise from the negative x axis
X = hor. = -104m.
Y = ver. = -185m.
a. D = sqrt(x^2 + y^2),
D = sqrt((-104)^2 + (-185)^2) = 212.2m.
b. tanAr = Y / X = -185 / -104=1.7788,
Ar = 60.7 deg.
A = 60.7 + 180 = 240.7 deg(Q3).
Ar = reference or related angle.