Posted by Layla on Sunday, September 4, 2011 at 6:14pm.
p=.001, n=2000
a)Expected number of errors=np=2
b)P(k)=2000Ck*.001^k*.999^(2000-k)
c)P(0)=.999^2000
d)P(1)=2000*.001*.999^1999
e)P(k>=1)=1-P(0)
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