Posted by Ben on .
Thank you Mr. bobpursley. I am still unclear on a few things.
massethanol*Ceth(Tf7.7)+masswater*Cwater*(Tf27.1)=0
solve for Tf
17.75g ethanol x(Tf7.7)+31.6g water x (Tf27.1)=0
This is the algebra that I do not know how to derive to move to the next step. Do I add it all to the other side of the equation or do I divide by everything on the left except for Tf?
Thanks again

chemistry f/u 
bobpursley,
This is pretty basic algebra.
Tf[17.75*Ceth +31.6*Cwater] 17.7(Ceth)(7.7)  31`.6*Cwat*27.1=0
check that.
then add the last two terms to both sides.
Then, divide both sides by the quantity in [].
If you really can't do this level of algebra, you need a math tutor now, or chemistry will increasingly grow onerous.
Math is the language for chemicalreactions.