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April 24, 2014

April 24, 2014

Posted by **Ben** on Sunday, September 4, 2011 at 4:50pm.

massethanol*Ceth(Tf-7.7)+masswater*Cwater*(Tf-27.1)=0

solve for Tf

17.75g ethanol x(Tf-7.7)+31.6g water x (Tf-27.1)=0

This is the algebra that I do not know how to derive to move to the next step. Do I add it all to the other side of the equation or do I divide by everything on the left except for Tf?

Thanks again

- chemistry f/u -
**bobpursley**, Sunday, September 4, 2011 at 4:55pmThis is pretty basic algebra.

Tf[17.75*Ceth +31.6*Cwater] -17.7(Ceth)(7.7) - 31`.6*Cwat*27.1=0

check that.

then add the last two terms to both sides.

Then, divide both sides by the quantity in [].

If you really can't do this level of algebra, you need a math tutor now, or chemistry will increasingly grow onerous.

Math is the language for chemicalreactions.

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