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December 22, 2014

December 22, 2014

Posted by **Natalie** on Sunday, September 4, 2011 at 4:33pm.

y= (lnx)/(3+4lnx)

Should I start by using the quotient rule?

- Calculus -
**bobpursley**, Sunday, September 4, 2011 at 4:46pmYou could, or...

y= (lnx)*1/(2+lnx)

y'= 1/x * 1/(2+lnx) - ln(x)/(2+lnx)^2 * 1/x

- Calculus -
**Damon**, Sunday, September 4, 2011 at 4:47pmhttp://www.wolframalpha.com/widgets/view.jsp?id=bf1b2f4b901c21a1d8645018ea9aeb05

put

(lnx)/(3+4lnx)

in as your function

click on differentiate

click on "show steps"

- Calculus -
**Damon**, Sunday, September 4, 2011 at 4:50pmDerivative:

Show steps

3/(x (4 log(x)+3)^2)

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