Posted by Natalie on Sunday, September 4, 2011 at 4:33pm.
You could, or...
y= (lnx)*1/(2+lnx)
y'= 1/x * 1/(2+lnx) - ln(x)/(2+lnx)^2 * 1/x
http://www.wolframalpha.com/widgets/view.jsp?id=bf1b2f4b901c21a1d8645018ea9aeb05
put
(lnx)/(3+4lnx)
in as your function
click on differentiate
click on "show steps"
Derivative:
Show steps
3/(x (4 log(x)+3)^2)
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