Posted by **Natalie** on Sunday, September 4, 2011 at 4:31pm.

Find the derivative of y with respect to x.

y= [(x^5)/5]lnx-[(x^5)/25]

How would I go about doing this?

Should I use the product rule to separate

(x^5)/5]lnx ?

## Answer This Question

## Related Questions

- Calculus 1 - Find the derivative of y with respect to x. y=(x^6/6)(lnx)-(x^6/36...
- College Calc - Problem: y=sqrtx ^1/x. Find DY/DX. ln(f(x))=lnx^1/2x or lnx to ...
- Calculus - Find the derivative of y with respect to x. y= (lnx)/(3+4lnx) Should ...
- L'Hopital's rule - Find lim x->1+ of [(1/(x-1))-(1/lnx)]. Here is my work...
- calculus - (a) find the intervals on which f is incrs or decrs. (b) find the ...
- calculus - sorry to ask a second question so soon, but i'm just not getting this...
- Calculus - what is the limit as h approaches 0 of ((x+h)^pi-x^pi)/h? Multiple ...
- Calculus - Find the derivatives, dy/dx for the following functions. a. x^2y^4 = ...
- Calculus - L'Hospital's Rule Lim(lnx)^(x-1) x->1+ This is what I did so far...
- calculus - find the following derivatives: f(x) = (2x+5)/(x^2-3) f'(x)= (2)*(x^2...

More Related Questions