Homework Help: Calculus

Posted by Natalie on Sunday, September 4, 2011 at 4:31pm.

Find the derivative of y with respect to x.
y= [(x^5)/5]lnx-[(x^5)/25]

How would I go about doing this?
Should I use the product rule to separate
(x^5)/5]lnx ?

Calculus - bobpursley, Sunday, September 4, 2011 at 4:51pm
I would change the variable, let u= x^5/5

then

y= u ln x-u
y'=u/x + u' lnx -u'

and surely you can find u'

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