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February 26, 2015

February 26, 2015

Posted by **Natalie** on Sunday, September 4, 2011 at 4:31pm.

y= [(x^5)/5]lnx-[(x^5)/25]

How would I go about doing this?

Should I use the product rule to separate

(x^5)/5]lnx ?

- Calculus -
**bobpursley**, Sunday, September 4, 2011 at 4:51pmI would change the variable, let u= x^5/5

then

y= u ln x-u

y'=u/x + u' lnx -u'

and surely you can find u'

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